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Free and unlimited download of Ko Song Mp3, Ko Movie Song Download, Ko Tamil Movie Songs Download Ko Song. Download Ko Bollywood Movie Song For Free Download. Ko Songs By Ajith Kumar Download Full Movie.Q: Sort documents by date in one collection and all documents in another I’m trying to sort a collection based on the date of a particular document in another collection. I’ve read the following topics: collectionA.find().sort() collectionA.sort() How to sort date and update records? document.sort() I’m trying to do something similar to the following, which is running in Node: db.collectionA.find({ _id: self.recordId }).sort(‘_id’, ‘desc’) I would like to sort a collection, and then all the documents in another collection, but the sample code above throws an error. Is there a way to use this sort method to call on both collections at the same time? Or is there another method I should be using? Thank you! A: You’re looking for the aggregation framework, specifically the $unwind stage: db.collectionA.aggregate([ { “$unwind”: “$transactions” }, { “$sort”: { “_id”: 1 } }, { “$group”: { “_id”: “$_id”, “count”: { “$sum”: 1 } } } ]) If transactions is an array, then this will process each item in the array. If there is only one transaction, then you’ll get back the entire document. In addition to that, you might also want to include a $limit stage to limit the number of documents returned: db.collectionA.aggregate([ { “$unwind”: “$transactions” }, { “$sort”: { “_id”: 1 } }, { “$group”: { “_id”: “$_id”, “count”: { “$sum”: 1 } } }, { “$project”: { “_id”: 0, “count”: 1 } }, { “$limit”: 1 } ]) And finally, if you just want to get the _id and count back from each document, you can use the $facet stage for that. db.collectionA.aggregate([



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