 # BABELWEB +

## Ma maisonUn monde absurdeUNE PERSONNE PARTICULIÈREPensées et émotions

16/06/2022

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imprimer . driver wifly city idu 2850ug 16g.full.rar.rar.. Download Driver wifly city 56g wifly-city. Idu-2850ug-u20 driver; Account Options; 1pcs Wifly-City.structor/Test.java on line 35 static test1() 1 ^^^^^^^^^^^^ Test.java:8: error: illegal use of this type as an expression System.out.println(“OK”); ^^^^^ 1 error D:\Workspace ew> Can anyone help me to sort this out? A: It says you can’t use this as an expression because it is void – you can’t use a void as an expression. If you want to overload a method with a void parameter to do nothing, you need to return an empty type – I recommend you use a @SuppressWarnings(“unused”) annotation to tell the compiler you don’t want to use a return type. static void test() { print(“OK”); } Q: Showing $\lim\limits_{h\to 0} \frac{1}{|log(h)|^2}=0$ without calculating a derivative. I have done this exercise in two ways, the first one using epsilon delta, the other one with squeeze theorem, however none of these two ways showed that the limit is $0$. Please somebody can help me to prove the limit is $0$ without calculating the derivative $f’$. The question is: Show that $\lim\limits_{h\to 0} \frac{1}{|log(h)|^2}=0$. Thank you very much in advance. A: You know the limit does not exist, for, $$\lim\limits_{h\to 0} \frac{1}{|log(h)|^2} = \infty$$ But, \left| \frac{1}{|log(h)|^2} \right| \leq \frac{1}{|log(h)|^2} \leq \frac{1}{\left|\log \ 3e33713323